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Question -

Find the equation to the straight line which cuts off equal positive intercepts on the axes and their product is 25.



Answer -

Given:

a = b and ab = 25

Let us find theequation of the line which cutoff intercepts on the axes.

 a2 =25

a = 5 [consideringonly positive value of intercepts]

By using the formula,

The equation of theline with intercepts a and b is x/a + y/b = 1

x/5 + y/5 = 1

By taking LCM

x + y = 5

The equation of lineis x + y = 5

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