Question -
Answer -
(i) Cutting off intercepts3 and 2 from the axes.
Given:
a = 3, b = 2
Let us find theequation of line cutoff intercepts from the axes.
By using the formula,
The equation of theline is x/a + y/b = 1
x/3 + y/2 = 1
By taking LCM,
2x + 3y = 6
∴ The equation of linecut off intercepts 3 and 2 from the axes is 2x + 3y = 6
(ii) Cutting off intercepts-5 and 6 from the axes.
Given:
a = -5, b = 6
Let us find theequation of line cutoff intercepts from the axes.
By using the formula,
The equation of theline is x/a + y/b = 1
x/-5 + y/6 = 1
By taking LCM,
6x – 5y = -30
∴ The equation of linecut off intercepts 3 and 2 from the axes is 6x – 5y = -30