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Question -

Find the equation of the side BC of the triangle ABC whose vertices are A (-1, -2), B (0, 1) and C (2, 0) respectively. Also, find the equation of the median through A (-1, -2).



Answer -

Given:

The vertices oftriangle ABC are A (-1, -2), B(0, 1) and C(2, 0).

Let us find theequation of median through A.

So, the equation of BCis

By using the formula,

x + 2y – 2 = 0

Let D be the midpointof median AD,

4y + 8 = 5x + 5

5x – 4y – 3 = 0

∴ The equation of lineBC is x + 2y – 2 = 0

The equation of medianis 5x – 4y – 3 = 0

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