Question -
Answer -
A line which ispassing through (1, 2)
To Find: The equationof a straight line.
By using the formula,
The equation of lineis [y – y1 = m(x – x1)]
Here, sin θ = 3/5
We know, sin θ =perpendicular/hypotenuse
= 3/5
So, according toPythagoras theorem,
(Hypotenuse)2 =(Base)2 + (Perpendicular)2
(5)2 =(Base)2 + (3)2
(Base) = √(25 – 9)
(Base)2 =√16
Base = 4
Hence, tan θ =perpendicular/base
= 3/4
The slope of the line,m = tan θ
= 3/4
The line passingthrough (x1,y1) = (1,2)
The required equationof line is y – y1 = m(x – x1)
Now, substitute thevalues, we get
y – 2= (¾) (x – 1)
4y – 8 = 3x – 3
3x – 4y + 5 = 0
∴ The equation of lineis 3x – 4y + 5 = 0