Question -
Answer -
Given:
A line which ispassing through (–2, 3), the angle is 45o.
By using the formula,
The equation of lineis [y – y1 = m(x – x1)]
Here, angle, θ =45o
The slope of the line,m = tan θ
m = tan 45o
= 1
The line passingthrough (x1, y1) = (–2, 3)
The required equationof line is y – y1 = m(x – x1)
Now, substitute thevalues, we get
y – 3 = 1(x – (– 2))
y – 3 = x + 2
x – y + 5 = 0
∴The equation of lineis x – y + 5 = 0