Question -
Answer -
(i) With slope 2 and y –intercept 3
The slope is 2 and thecoordinates are (0, 3)
Now, the requiredequation of line is
y = mx + c
Substitute the values,we get
y = 2x + 3
(ii) With slope – 1/ 3 andy – intercept – 4
The slope is – 1/3 andthe coordinates are (0, – 4)
Now, the requiredequation of line is
y = mx + c
Substitute the values,we get
y = -1/3x – 4
3y + x = – 12
(iii) With slope – 2 andintersecting the x–axis at a distance of 3 units to the left of origin
The slope is – 2 andthe coordinates are (– 3, 0)
Now, the requiredequation of line is y – y1 = m (x – x1)
Substitute the values,we get
y – 0 = – 2(x + 3)
y = – 2x – 6
2x + y + 6 = 0