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Question -

Find the equation of the parallel to x–axis and passing through (3, –5).



Answer -

Given: A line which isparallel to x–axis and passing through (3, –5)

By using the formula,

The equation of line:[y – y1 = m(x – x1)]

We know that theparallel lines have equal slopes

And, the slope ofx–axis is always 0

Then

The slope of line, m =0

Coordinates of lineare (x1, y1) = (3, –5)

The equation of line =y – y1 = m(x – x1)

Now, substitute thevalues, we get

y – (– 5) = 0(x – 3)

y + 5 = 0

The equation of lineis y + 5 = 0

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