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Question -

Find the equation of a straight line through the point of intersection of the lines 4x – 3y = 0 and 2x – 5y + 3 = 0 and parallel to 4x + 5 y + 6 = 0.



Answer -

Given:

Lines 4x – 3y = 0 and2x – 5y + 3 = 0 and parallel to 4x + 5 y + 6 = 0

The equation of thestraight line passing through the points of intersection of 4x − 3y =0 and 2x − 5y + 3 = 0 is given below:

4x − 3y+ λ (2x − 5y + 3) = 0

(4 + 2λ)x +(− 3 − 5λ)y + 3λ = 0

The required line isparallel to 4x + 5y + 6 = 0 or, y = -4x/5 – 6/5

λ = -16/15

The required equationis

28x + 35y – 48 = 0

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