The Total solution for NCERT class 6-12
Given:
The given lines are
3x − 4y + a= 0 … (1)
3x − 4y + 3a= 0 … (2)
4x − 3y − a= 0 … (3)
4x − 3y − 2a= 0 … (4)
Let us prove, the areaof the parallelogram formed by the lines 3x – 4y + a = 0, 3x – 4y + 3a = 0, 4x– 3y – a = 0 and 4x – 3y – 2a = 0 is 2a2/7 sq. units.
From above solution,we know that
Hence proved.