The Total solution for NCERT class 6-12
Given:
The lines 2x + 3y = 21and 3x – 4y + 11 = 0
Solving the lines 2x +3y = 21 and 3x − 4y + 11 = 0 we get:
x = 3, y = 5
So, the point ofintersection of 2x + 3y = 21 and 3x − 4y + 11 = 0 is (3, 5).
Now, the perpendiculardistance d of the line 8x + 6y + 5 = 0 from the point (3, 5) is
∴ The distance is59/10.