Question -
Answer -
Given:
A (1, 3) and B (3, 1)be the points joining the perpendicular bisector
Let C be the midpointof AB.
So, coordinates of C =[(1+3)/2, (3+1)/2]
= (2, 2)
Slope of AB = [(1-3) /(3-1)]
= -1
Slope of theperpendicular bisector of AB = 1
Thus, the equation ofthe perpendicular bisector of AB is given as,
y – 2 = 1(x – 2)
y = x
x – y = 0
∴ The required equationis y = x.