Question -
Answer -
Given:
L1 =(b + c)x + ay + 1 = 0
L2 =(c + a)x + by + 1 = 0
L3 =(a + b)x + cy + 1 = 0
The given lines can bewritten as follows:
(b + c) x + ay + 1 = 0… (1)
(c + a) x + by + 1 = 0… (2)
(a + b) x + cy + 1 = 0… (3)
Consider the followingdeterminant.
Hence proved, thegiven lines are concurrent.