Question -
Answer -
Given:
y = √3x + 1…… (1)
y = 4 ……. (2)
y = – √3x + 2……. (3)
Let us assume intriangle ABC, let equations (1), (2) and (3) represent the sides AB, BC and CA,respectively.
By solving equations(1) and (2), we get
x = √3, y = 4
Thus, AB and BCintersect at B(√3,4)
Now, solving equations(1) and (3), we get
x = 1/2√3, y = 3/2
Thus, AB and CAintersect at A (1/2√3, 3/2)
Similarly, solvingequations (2) and (3), we get
x = -2/√3, y = 4
Thus, BC and ACintersect at C (-2/√3,4)
Now, we have:
Hence proved, thegiven lines form an equilateral triangle.