Question -
Answer -
(i)┬а2x тАУ y + 3 = 0 and x +y тАУ 5 = 0
Given:
The equations of thelines are as follows:
2x тИТ y + 3 = 0 тАж (1)
x + y тИТ 5 = 0 тАж (2)
Let us find the pointof intersection of pair of lines.
By solving (1) and (2)using cross тАУ multiplication method, we get
x = 2/3 and y = 13/3
тИ┤┬аThe point ofintersection is (2/3, 13/3)
(ii)┬аbx + ay = ab and ax +by = ab
Given:
The equations of thelines are as follows:
bx + ay тИТ ab = 0тАж (1)
ax + by = ab┬атЗТ┬аax + by тИТ ab = 0 тАж (2)
Let us find the pointof intersection of pair of lines.
By solving (1) and (2)using cross тАУ multiplication method, we get
тИ┤┬аThe point ofintersection is (ab/a+b, ab/a+b)