The Total solution for NCERT class 6-12
Thickness of steel = 0.25 cm =┬а1/4cmInside radius of the hemispherical bowl (r) = 5 cmтИ┤ Outer radius (R) = 5 +0.25 = 5.25 cmтИ┤ Volume of the steel used=┬а╧А(R3┬атАУ r3)