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Question -

1 + 3 + 7 + 13 + 21 + тАж



Answer -

Let┬аTn┬аbethe┬аnth term and Sn┬аbe the sum to n terms of the given series.

We have,

Sn┬а= 1+ 3 + 7 + 13 + 21 + тАжтАжтАжтАж. + Tn-1┬а+ Tn┬атАж (1)

Equation (1) can berewritten as:

Sn┬а= 1+ 3 + 7 + 13 + 21 + тАжтАжтАжтАж. + Tn-1┬а+ Tn┬атАжтАж..(2)

By subtracting (2)from (1) we get

Sn┬а= 1+ 3 + 7 + 13 + 21 + тАжтАжтАжтАж. + Tn-1┬а+ Tn

Sn┬а= 1+ 3 + 7 + 13 + 21 + тАжтАжтАжтАж. + Tn-1┬а+ Tn

0 = 1 + [2 + 4 + 6 + 8+ тАж + (Tn┬атАУ Tn-1)] тАУ Tn

The difference betweenthe successive terms are 2, 4, 6, 8

So these differencesare in A.P

Now,

тИ┤ The sum of the seriesis n/3 (n2┬а+ 2)

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