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Question -

1 + (1 + 2) + (1 + 2 + 3) + (1 + 2 + 3 + 4) + … to n terms



Answer -

Let Tn bethe nth term of the given series.

We have:

Tn =n(n+1)/2

= (n2 +n)/2

Now, let Sn bethe sum of n terms of the given series.

We have:

The sum of the seriesis [n(n+1)(n+2)]/6

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