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Question -

If a, b, c are in G.P., prove that 1/loga m , 1/logb m,1/logc m are in A.P.



Answer -

Given:

a, b and c are in GP

b2 =ac {property of geometric mean}

Apply log on bothsides with base m

logm b2 =logm ac

logm b2 =logm a + logm c {using property of log}

2logm b= logm a + logm c

2/logb m= 1/loga m + 1/logc m

1/loga m, 1/logb m, 1/logc m are in A.P.

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