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Question -

Prove that :
(91/3 . 91/9 . 91/27 ….∞) = 3.



Answer -

Let us consider theLHS

(91/3 .91/9 . 91/27 ….∞)

This can be written as

91/3 + 1/9 + 1/27+ …∞

So let us consider m =1/3 + 1/9 + 1/27 + … ∞

Where, a = 1/3, r =(1/9) / (1/3) = 1/3

By using the formula,

S =a/(1 – r)

= (1/3) / (1 – (1/3))

= (1/3) / ((3-1)/3)

= (1/3) / (2/3)

= ½

So, 9m =91/2 = 3 = RHS

Hence proved.

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