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Question -

Which term of the progression 18, -12, 8, … is512/729 ?



Answer -

By using the formula,

Tn =arn-1

a = 18

r = t2/t1 =(-12/18)

= -2/3

Tn =512/729

n = ?

Tn =arn-1

512/729 = 18 (-2/3)n-1

29/(729 ×18) = (-2/3)n-1

29/36 ×1/2×32 = (-2/3)n-1

(2/3)8 =(-1)n-1 (2/3)n-1

8 = n – 1

n = 8 + 1

= 9

 9th termof the Progression is 512/729

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