Question -
Answer -
The nth term from theend is given by:
an = l(1/r)n-1 where, l is the last term, r is the common ratio, n isthe nth term
Given: last term, l =162
r = t2/t1 =(2/9) / (2/27)
= 2/9 × 27/2
= 3
n = 4
So, an =l (1/r)n-1
a4 =162 (1/3)4-1
= 162 (1/3)3
= 162 × 1/27
= 6
∴ 4th termfrom last is 6.