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Question -

Find the domain and range of the following real function:
(i) f(x) = тАУ|x| (ii) f(x) = тИЪ(9 тАУ x2)┬а



Answer -

(i)┬аGiven,

f(x) = тАУ|x|,┬аx┬атИИ┬аR

We know that,

As┬аf(x)is defined for┬аx┬атИИ┬аR, the domain of┬аf┬аis┬аR.

It is also seen thatthe range of┬аf(x) = тАУ|x| is all real numbers exceptpositive real numbers.

Therefore, the rangeof┬аf┬аis given by (тАУтИЮ, 0].

(ii)┬аf(x) = тИЪ(9 тАУx2)

As тИЪ(9 тАУ x2)┬аisdefined for all real numbers that are greater than or equal to тАУ3 and less thanor equal to 3, for 9 тАУ x2┬атЙе 0.

So, the domainof┬аf(x) is {x: тАУ3 тЙд┬аx┬атЙд 3} or [тАУ3,3].

Now,

For any value of┬аx┬аinthe range [тАУ3, 3], the value of┬аf(x) will lie between 0 and3.

Therefore, the rangeof┬аf(x) is {x: 0 тЙд┬аx┬атЙд 3} or [0, 3].

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