The Total solution for NCERT class 6-12
If the product of zeros of the polynomial f(x) = ax3 – 6x2 + 11x – 6 is 4, then a =
Answer - 11 : - (a)
f(x) = ax3 – 6x2 + 11x – 6
If zeros of the polynomial f(x) = x3 – 3px2 + qx – r are in AP, then(a) 2p3 = pq – r(b) 2p3 = pq + r(c) p3 = pq – r(d) None of these
Answer - 12 : - (a)
f(x) = x3 – 3px2 + qx – rHere a = 1, b = -3p, c = q, d= -rZeros are in APLet the zeros be α – d, α, α + d
If the product of two zeros of the polynomial f(x) = 2x3 + 6x2 – 4x + 9 is 3, then its third zero is
Answer - 13 : - (b)
Answer - 14 : - (a)
Answer - 15 : -
(b) In the previous questionsRemainder = 0(b – ac + ab2) = 0b + ab2 = ac=> ac = b (1 + ab) = b (1 + 1) = 2b
If one root of the polynomial f(x) = 5x2 + 13x + k is reciprocal of the other, then the value of k is(a) 0(b) 5(c) 1/6
(d) 6
Answer - 16 : - (b)
Answer - 17 : - (c)
If α, β, γ are the zeros of the polynomial f(x) = ax3 + bx2 + cx + d, then α2 + β2 + γ2 =
Answer - 18 : - (d)
Answer - 19 : - (b)
Answer - 20 : - (b)