The Total solution for NCERT class 6-12
If f(x) = ax2 + bx + c has no real zeros and a + b + c< 0, then(a) c = 0(b) c > 0(c) c < 0(d) None of these
(d)
f(x) = ax2 + bx + cZeros are not realb2 – 4ac < 0 ….(i)but a + b + c < 0b < – (a + c)Squaring both sides b2 < (a + c)2=> (a + c)2 – 4ac < 0 {From (i)}=> (a – c)2 < 0=> a – c < 0=> a < c