Question -
Answer -
(i)(x+4)(x┬а+10)┬а
Using the identity, (x+a)(x+b) = x┬а2+(a+b)x+ab
[Here, a = 4 and b = 10]
We get,
(x+4)(x+10) = x2+(4+10)x+(4├Ч10)
= x2+14x+40
(ii)(x+8)(x┬атАУ10)┬а┬а┬а┬а┬а
Using the identity, (x+a)(x+b) = x┬а2+(a+b)x+ab
[Here, a = 8 and b = тИТ10]
We get,
(x+8)(xтИТ10) = x2+(8+(тИТ10))x+(8├Ч(тИТ10))
= x2+(8тИТ10)xтАУ80
= x2тИТ2xтИТ80
(iii) (3x+4)(3xтАУ5)
Using the identity, (x+a)(x+b) = x┬а2+(a+b)x+ab
[Here, x = 3x, a = 4 and b= тИТ5]
We get,
(3x+4)(3xтИТ5) = (3x)2+[4+(тИТ5)]3x+4├Ч(тИТ5)
= 9x2+3x(4тАУ5)тАУ20
= 9x2тАУ3xтАУ20
(iv) (y2+3/2)(y2-3/2)
Using the identity, (x+y)(xтАУy) = x2тАУy┬а2
[Here, x = y2andy = 3/2]
We get,
(y2+3/2)(y2тАУ3/2) = (y2)2тАУ(3/2)2
= y4тАУ9/4