Question -
Answer -
Let the number of тВ╣5 coins be x.
Then,
number тВ╣2 coins = 3x
and, number of тВ╣1 coins = (160 тАУ 4x) Now,
Value of тВ╣5 coins = x ├Ч 5 = 5x
Value of тВ╣2 coins = 3x ├Ч 2 = 6x
Value of тВ╣1 coins = (160 тАУ 4x) ├Ч 1 = (160 тАУ 4x)
According to the question,
5x + 6x + (160 тАУ 4x) = 300
тЗТ 11x + 160 тАУ 4x = 300
тЗТ 7x = 140
тЗТ x = 140/7
тЗТ x = 20
Number of тВ╣5 coins = x = 20
Number of тВ╣2 coins = 3x = 60
Number of тВ╣1 coins = (160 тАУ 4x) = 160 тАУ 80 = 80