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Question -

Find┬аgof┬аand┬аfog┬аwhen┬аf:┬аR┬атЖТ┬аR┬аand┬аg┬а:┬аR┬атЖТ┬аR┬аisdefined by┬а

(i) f(x) = 2x┬а+ 3 and ┬аg(x) =┬аx2┬а+ 5.

(ii) f(x) = 2x┬а+┬аx2┬аand┬а┬аg(x)=┬аx3

(iii) f┬а(x)┬а=┬аx2┬а+ 8┬аand g(x)┬а=3x3┬а+ 1

(iv) f (x) =┬аx┬аand┬аg(x) = |x|┬а

(v) f(x) =┬аx2┬а+ 2x┬атИТ 3 and┬а┬аg(x) =3x┬атИТ 4┬а

(vi) f(x) = 8x3┬аand┬а┬аg(x) =┬аx1/3



Answer -

(i)Given,┬аf:┬аR┬атЖТ┬аR┬аand┬аg:┬аR┬атЖТ┬аR

So,┬аgof:┬аR┬атЖТ┬аR┬аand┬аfog:┬аR┬атЖТ┬аR

Also given that f(x) =2x┬а+ 3 and┬аg(x) =┬аx2┬а+ 5

Now, (gof) (x) = g (f (x))

= g┬а(2x┬а+3)

=┬а(2x┬а+ 3)2┬а+ 5

=┬а4x2+ 9 + 12x┬а+5

=4x2+┬а12x┬а+ 14

Now, (fog) (x) = f (g(x))

= f (x2┬а+ 5)

=┬а2┬а(x2┬а+ 5) +3

=┬а2┬аx2+ 10 + 3

=┬а2x2┬а+ 13

(ii)Given,┬аf:┬аR┬атЖТ┬аR┬аand┬аg:┬аR┬атЖТ┬аR

so,┬аgof:┬аR┬атЖТ┬аR┬аand┬аfog:┬аR┬атЖТ┬аR

f(x) =2x┬а+┬аx2┬аand┬аg(x) =┬аx3

(gof)┬а(x)=┬аg┬а(f┬а(x))

=┬аg┬а(2x+x2)

=┬а(2x+x2)3

Now, (fog)┬а(x)=┬аf┬а(g┬а(x))

=┬аf┬а(x3)

=┬а2┬а(x3)+ (x3)2

= 2x3┬а+x6

(iii)Given,┬аf:┬аR┬атЖТ┬аR┬аand┬аg:┬аR┬атЖТ┬аR

So,┬аgof:┬аR┬атЖТ┬аR and┬аfog:┬аR┬атЖТ┬аR

f(x) =┬аx2┬а+8┬а and┬аg(x) = 3x3┬а+ 1

(gof)┬а(x)=┬аg┬а(f┬а(x))

=┬аg┬а(x2┬а+┬а8)

=┬а3┬а(x2+8)3┬а+┬а1

Now, (fog)┬а(x)=┬аf┬а(g┬а(x))

=┬аf┬а(3x3┬а+┬а1)

=┬а(3x3+1)2┬а+┬а8

=┬а9x6┬а+┬а6x3┬а+┬а1+┬а8

= 9x6┬а+6x3┬а+ 9

(iv)Given,┬аf:┬аR┬атЖТ┬аR┬аand┬аg:┬аR┬атЖТ┬аR

So,┬аgof:┬аR┬атЖТ┬аR┬аand┬аfog:┬аR┬атЖТ┬аR

f(x)=┬аx┬аand┬аg(x) = |x|

(gof)┬а(x)=┬аg┬а(f┬а(x))

=┬аg┬а(x)

=┬а|x|

Now (fog)┬а(x)=┬аf┬а(g┬а(x))

=┬аf┬а(|x|)

=┬а|x|

(v)Given,┬аf:┬аR┬атЖТ┬аR┬аand┬аg:┬аR┬атЖТ┬аR

So,┬аgof:┬аR┬атЖТ┬аR┬аand┬аfog:┬аR┬атЖТ┬аR

f(x) =┬аx2┬а+2x┬атИТ 3 and┬аg(x) = 3x┬атИТ 4

(gof)┬а(x)=┬аg┬а(f(x))

=┬аg┬а(x2┬а+2x тИТ 3)

=┬а3┬а(x2┬а+2x тИТ 3)┬атИТ 4

=┬а3x2┬а+┬а6x┬атИТ┬а9┬атИТ┬а4

=┬а3x2┬а+6x тИТ 13

Now, (fog)┬а(x)=┬аf┬а(g┬а(x))

=┬аf┬а(3x тИТ 4)

=┬а(3x┬атИТ┬а4)2┬а+2┬а(3x┬атИТ┬а4)┬атИТ3

=┬а9x2┬а+16 тИТ 24x + 6x тАУ 8 тИТ 3

=┬а9x2┬атИТ18x┬а+┬а5

(vi)Given,┬аf:┬аR┬атЖТ┬аR┬аand┬аg:┬аR┬атЖТ┬аR

So,┬аgof:┬аR┬атЖТ┬аR┬аand┬аfog:┬аR┬атЖТ┬аR

f(x) = 8x3┬аand┬аg(x)=┬аx1/3

(gof)┬а(x)=┬аg┬а(f┬а(x))

=┬аg┬а(8x3)

= (8x3)1/3

= [(2x)3]1/3

=┬а2x

Now, (fog)┬а(x)=┬аf┬а(g┬а(x))

= f (x1/3)

= 8 (x1/3)3

=┬а8x

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