The Total solution for NCERT class 6-12
माना sin-1x = θ ∴ sin θ = xपुनः sin 3θ = 3 sin3 θ – 4 sin० θ⇒ sin 3θ = 3x – 4x3⇒ 3θ = sin-1(3x– 4x3)∴ 3sin-1x =sin-1(3x – 4x3) इति सिद्धम्