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Question -

A farmer buys a used tractor for ₹ 12000. He pays ₹ 6000 cash and agrees to pay the balance in annual instalments of ₹ 500 plus 12% interest on the unpaid amount. How much the tractor cost him?



Answer -

Given: Price ofthe tractor is ₹12000.

We need tofind the total cost of the tractor if he buys it in installments.

Total price = ₹ 12000

Paid amount = ₹ 6000

Unpaid amount = ₹12000 – 6000 = ₹ 6000

He pays remaining ₹6000 in ‘n’ number of installments of ₹ 500 each.

So, n = 6000/500 = 12

Cost incurred by himto pay remaining 6000 is

The AP will be:

(500 + 12% of 6000) +(500 + 12% of 5500) + … up to 12 terms

500 × 12 + 12% of(6000 + 5500 + … up to 12 terms)

By using the formula,

Sn =n/2 [2a + (n – 1)d]

n = 12, a = 6000, d =-500

S12 =500×12 + 12/100 × 12/2 [2(6000) + (12-1) (-500)]

= 6000 + 72/100 [12000+ 11 (-500)]

= 6000 + 72/100 [12000– 5500]

= 6000 + 72/100 [6500]

= 6000 + 4680

= 10680

Total cost = 6000 +10680

= 16680

The total cost of thetractor if he buys it in installment is ₹ 16680.

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