Question -
Answer -
Let A1, A2,A3, A4, A5, A6 be the 7 AMbetween 15 and – 13
Then, 15, A1,A2, A3, A4, A5, A6, – 13are in AP
By using the formula,
an = a+ (n – 1)d
an =-13, a = 15, n = 8
so,
-13 = 15 + (8 – 1)d
-13 = 15 + 7d
7d = -13 – 15
7d = -28
d = -4
So,
A1 = a+ d = 15 – 4 = 11
A2 =A1 + d = 11 – 4 = 7
A3 =A2 + d = 7 – 4 = 3
A4 =A3 + d = 3 – 4 = -1
A5 =A4 + d = -1 – 4 = -5
A6 =A5 + d = -5 – 4 = -9