Question -
Answer -
Let A1, A2,A3, A4, A5, A6, A7 bethe 7 AMs between 2 and 17
Then, 2, A1,A2, A3, A4, A5, A6, A7,17 are in AP
By using the formula,
an = a+ (n – 1)d
an =17, a = 2, n = 9
so,
17 = 2 + (9 – 1)d
17 = 2 + 9d – d
17 = 2 + 8d
8d = 17 – 2
8d = 15
d = 15/8
So,
A1 = a+ d = 2 + 15/8 = 31/8
A2 = A1 +d = 31/8 + 15/8 = 46/8
A3 = A2 +d = 46/8 + 15/8 = 61/8
A4 = A3 +d = 61/8 + 15/8 = 76/8
A5 = A4 +d = 76/8 + 15/8 = 91/8
A6 = A5 +d = 91/8 + 15/8 = 106/8
A7 = A6 +d = 106/8 + 15/8 = 121/8
∴ the 7 AMs between 2and 7 are 31/8, 46/8, 61/8, 76/8, 91/8, 106/8, 121/8