Question -
Answer -
Given:
Sum of four terms is50.
Let us assume thesefour terms as a – 3d, a – d, a + d, a + 3d
It is given that, sumof these terms is 4a = 50
So, a = 50/4
= 25/2 … (i)
It is also given thatthe greatest number is 4 time the least
a + 3d = 4(a – 3d)
Substitute the valueof a = 25/2, we get
(25+6d)/2 = 50 – 12d
30d = 75
d = 75/30
= 25/10
= 5/2 … (ii)
Hence, the terms of APare a – 3d, a – d, a + d, a + 3d which is 5, 10, 15, 20