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Question -

Find the 7th term in theexpansion of (3x2 – 1/x3)10.



Answer -

Given:

(3x2 –1/x3)10

Let us consider the 7th termas T7

So,

T7 = T6+1

10C6 (3x2)10-6 (-1/x3)6

10C6 (3)4 (x)8 (1/x18)

= [10×9×8×7×81] /[4×3×2×x10]

= 17010 / x10

The 7th termof the expression (3x2 – 1/x3)10 is17010 / x10.

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