Question -
Answer -
Given:
(2x – 1/x2)25
The given expressioncontains 26 terms.
So, the 11th termfrom the end is the (26 − 11 + 1) th term from thebeginning.
In other words, the 11th termfrom the end is the 16th term from the beginning.
Then,
T16 =T15+1 = 25C15 (2x)25-15 (-1/x2)15
= 25C15 (210)(x)10 (-1/x30)
= – 25C15 (210 /x20)
Now we shall find the11th term from the beginning.
T11 =T10+1 = 25C10 (2x)25-10 (-1/x2)10
= 25C10 (215)(x)15 (1/x20)
= 25C10 (215 /x5)