Question -
Answer -
Given f (x) = (x – 1) ex + 1
Now differentiating the given equation with respect to x, we get
⇒ 
⇒ f’(x)= ex + (x – 1) ex
⇒ f’(x)= ex(1+ x – 1)
⇒ f’(x)= x ex
As given x > 0
⇒ ex >0
⇒ xex > 0
⇒ f’(x)> 0
Hence, condition for f(x) to be increasing
Thus f(x) is increasing on interval x > 0