Question -
Answer -
Given f (x) = e2x
⇒ 
⇒ f’(x)= 2e2x
For f(x) to be increasing, we must have
⇒ f’(x)> 0
⇒ 2e2x >0
⇒ e2x >0
Since, the value of e lies between 2 and 3
So, whatever be the power of e (that is x in domain R) will begreater than zero.
Thus f(x) is increasing on interval R