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Question -

Show that f(x) =cos2┬аx is a decreasing function on (0, ╧А/2).



Answer -

Given f (x) = cos2┬аx

тЗТ┬а

тЗТ┬аfтАЩ(x)= 2 cos x (тАУsin x)

тЗТ┬аfтАЩ(x)= тАУ2 sin (x) cos (x)

тЗТ┬аfтАЩ(x)= тАУsin2x

Now, as given x belongs to (0, ╧А/2).

тЗТ┬а2x┬атИИ┬а(0, ╧А)

тЗТ┬аSin(2x)> 0

тЗТ┬атАУSin(2x) < 0

тЗТ┬аfтАЩ(x)< 0

Hence, condition for f(x) to be decreasing

Thus f(x) is decreasing on interval┬а(0, ╧А/2).

Hence proved

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