Question -
Answer -
Given f(x) = x2 – 6x + 9
⇒ 
⇒ f’(x)= 2x – 6
⇒ f’(x)= 2(x – 3)
For f(x) let us find critical point, we must have
⇒ f’(x)= 0
⇒ 2(x– 3) = 0
⇒ (x– 3) = 0
⇒ x= 3
Clearly, f’(x) > 0 if x > 3 and f’(x) < 0 if x < 3
Thus, f(x) increases on (3, ∞) and f(x) is decreasing oninterval x ∈ (–∞,3)
Now, let us find coordinates of point
Equation of curve is f(x) = x2 – 6x + 9
Slope of this curve is given by
