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Question -

How many different selections of 4 books can be made from 10 different books, if
(i) there is no restriction
(ii) two particular books are always selected
(iii) two particular books are never selected



Answer -

Given:

Total number of books= 10

Total books to beselected = 4

(i) there is norestriction

Number of ways =choosing 4 books out of 10 books

10C4

By using the formula,

nCr = n!/r!(n – r)!

10C4 = 10! / 4! (10 – 4)!

= 10! / (4! 6!)

= [10×9×8×7×6!] / (4!6!)

= [10×9×8×7] /(4×3×2×1)

= 10×3×7

= 210 ways

(ii) two particular booksare always selected

Number of ways =select 2 books out of the remaining 8 books as 2 books are already selected.

8C2

By using the formula,

nCr = n!/r!(n – r)!

8C2 = 8! / 2! (8 – 2)!

= 8! / (2! 6!)

= [8×7×6!] / (2! 6!)

= [8×7] / (2×1)

= 4×7

= 28 ways

(iii) two particular booksare never selected

Number of ways = select4 books out of remaining 8 books as 2 books are already removed.

8C4

By using the formula,

nCr = n!/r!(n – r)!

8C4 = 8! / 4! (8 – 4)!

= 8! / (4! 4!)

= [8×7×6×5×4!] / (4!4!)

= [8×7×6×5] /(4×3×2×1)

= 7×2×5

= 70 ways

 The required no.of ways are 210, 28, 70.

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