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Question -

How many different products can be obtained by multiplying two or more of the numbers 3, 5, 7, 11 (without repetition)?



Answer -

Given that we need tofind the no. of ways of obtaining a product by multiplying two or more from thenumbers 3, 5, 7, 11.

Number of ways = (no.of ways of multiplying two numbers) + (no. of ways of multiplying threenumbers) + (no. of multiplying four numbers)

=┬а4C2┬а+┬а4C3┬а+┬а4C4

By using the formula,

nCr┬а= n!/r!(n тАУ r)!

= 12/2 + 4 + 1

= 6 + 4 + 1

= 11

тИ┤┬аThe total numberof ways of product is 11 ways.

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