Question -
Answer -
Given that we need tofind the no. of ways of obtaining a product by multiplying two or more from thenumbers 3, 5, 7, 11.
Number of ways = (no.of ways of multiplying two numbers) + (no. of ways of multiplying threenumbers) + (no. of multiplying four numbers)
= 4C2 + 4C3 + 4C4
By using the formula,
nCr = n!/r!(n – r)!
= 12/2 + 4 + 1
= 6 + 4 + 1
= 11
∴ The total numberof ways of product is 11 ways.