The Total solution for NCERT class 6-12
(ii) y = √x at x =9
(iii) y = x3 –x at x = 2
(iv) y = 2x2 +3 sin x at x = 0
(v) x = a (θ –sin θ), y = a (1 + cos θ) at θ = -π /2
(vi) x = a cos3 θ,y = a sin3 θ at θ = π /4
(vii) x = a(θ – sin θ), y = a (1 – cos θ) at θ = π /2
(viii) y = (sin 2x+ cot x + 2)2 at x = π /2
(ix) x2 +3y + y2 = 5 at (1, 1)
(x) x y = 6 at (1,6)
(i)
⇒ TheSlope of the normal = – 6
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
(ix)
(x)