The Total solution for NCERT class 6-12
Find a point on thecurve y = x2 where the Slope of the tangent is equal to the x –coordinate of the point.
Given the curve is y = x2
y = x2
Differentiating the above with respect to x
From (1) & (2), we get,
2x = x
⇒ x= 0.
Substituting this in y = x2, we get,
y = 02
⇒ y= 0
Thus, the required point is (0, 0)