MENU
Question -

Consider a cylindrical tub having radius as 5 cm and its length 9.8 cm. It is full of water. A solid in the form of a right circular cone mounted on a hemisphere is immersed in tub. If the radius of the hemisphere is 3.5 cm and the height of the cone outside the hemisphere is 5 cm, find the volume of water left in the tub.



Answer -

Given,

The radius of theCylindrical tub (r) = 5 cm

Height of theCylindrical tub (H) = 9.8 cm

Height of the coneoutside the hemisphere (h) = 5 cm

Radius of the hemisphere= 3.5 cm

Now, we know that

The volume of theCylindrical tub (V1) = πr2H

V1 =π(5)2 9.8

V1 =770 cm3

And, the volume of theHemisphere (V2) = 2/3 × π × r3

V2 = 2/3× 22/7 × 3.53

V2 =89.79 cm3

And, the volume of theHemisphere (V3) = 23 × π × r × 2h

V3 = 2/3× 22/7 × 3.52 × 5

V3 =64.14 cm3

Thus, total volume (V)= Volume of the cone + Volume of the hemisphere

= V2 +V3

V = 89.79 + 64.14 cm3 

= 154 cm3

So, the total volumeof the solid = 154 cm3

In order to find thevolume of the water left in the tube, we have to subtract the volume of thehemisphere and the cone from the volume of the cylinder.

Hence, the volume ofwater left in the tube = V1 – V2

= 770 – 154

= 616 cm3

Therefore, the volumeof water left in the tube is 616 cm3.

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
NodeJS Interview Questions Answers
ASP.Net Interview Questions Answers
Interview Questions Answers
×