Question -
Answer -
Given,
Diameter of thehemisphere = 3.5 m
So, the radius of thehemisphere (r) = 1.75 m
Height of the cylinder(h) = 14/3 m
We know that, volumeof the Cylinder = πr2 h1 = V1
V1 =π(1.75)2 x 14/3 m3
The volume of thehemispherical bottom = 2 × 2/3 × 22/7 × r3 = V2
V2 = 2/3× 22/7 × 1.753 m3
Therefore,
The total volume ofthe vessel (V) = volume of the cylinder + volume of the hemisphere
V = V1 +V2
V = π(1.75)2 x14/3 + 2/3 × 22/7 × 1.753
V = π(1.75)2 (14/3+ 2/3 x 1.75)
V = 56.15 m2
Hence, the volume ofthe vessel = V = 56.15 m3
Now,
Internal surface areaof solid (S) = Surface area of the cylinder + Surface area of the hemisphere
S = 2 πr h1 +2 πr2
S = 2 π(1.75)(143) + 2π(1.75)2
S = 70.51 m3
Therefore, theinternal surface area of the solid is 70.51 m3