Question -
Answer -
Given,
Height of the tent =77 dm
Height of a surmountedcone = 44 dm
Height of theCylindrical Portion = Height of the tent – Height of the surmounted Cone
= 77 – 44
= 33 dm = 3.3 m
And, given diameter ofthe cylinder (d) = 36 m
So, its radius (r) ofthe cylinder = 36/2 = 18 m
Let’s consider L asthe slant height of the cone.
Then, we know that
L2 = r2 +h2
L2 =182 + 3.32
L2 =324 + 10.89
L2 = 334.89
L = 18.3 m
Thus, slant height ofthe cone (L) = 18.3 m
Now, the CurvedSurface area of the Cylinder (S1) = 2πrh
S1 =2π (184.4) m2
And, the CurvedSurface area of the cone (S2) = πrL
S2 = π× 18 × 18.3 m2
So, the total curvedsurface of the tent (S) = S1 + S2
S = S1 +S2
S = (2π18 × 4.4)+ (π18 × 18.3)
S = 1533.08 m2
Hence, the totalCurved Surface Area (S) = 1533.08 m2
Next,
The cost of 1 m2 canvas= Rs 3.50
So, 1533.08 m2 ofcanvas will cost = Rs (3.50 x 1533.08)
= Rs 5365.8