Question -
Answer -
Given,
Height of the tent =77 dm
Height of a surmountedcone = 44 dm
Height of theCylindrical Portion = Height of the tent тАУ Height of the surmounted Cone
= 77 тАУ 44
= 33 dm = 3.3 m
And, given diameter ofthe cylinder (d) = 36 m
So, its radius (r) ofthe cylinder =┬а36/2 = 18 m
LetтАЩs consider L asthe slant height of the cone.
Then, we know that
L2┬а= r2┬а+h2
L2┬а=182┬а+ 3.32
L2┬а=324 + 10.89
L2┬а= 334.89
L = 18.3 m
Thus, slant height ofthe cone (L) = 18.3 m
Now, the CurvedSurface area of the Cylinder (S1) = 2╧Аrh
S1┬а=2╧А (184.4) m2┬а
And, the CurvedSurface area of the cone (S2) = ╧АrL
S2┬а= ╧А├Ч 18 ├Ч 18.3 m2┬а
So, the total curvedsurface of the tent (S) = S1┬а+ S2
S = S1┬а+S2
S = (2╧А18 ├Ч┬а4.4)+ (╧А18 ├Ч┬а18.3)
S = 1533.08 m2
Hence, the totalCurved Surface Area (S) = 1533.08 m2
Next,
The cost of 1 m2┬аcanvas= Rs 3.50
So, 1533.08 m2┬аofcanvas will cost = Rs (3.50 x 1533.08)
= Rs 5365.8