Given,
Diameter of thecylinder = 20 m
So, its radius of thecylinder (R) = 10 m
Height of the cylinder(h1) = 2.5 m
Radius of the cone =Radius of the cylinder (r) = 15 m
Height of the Cone (h2)= 7.5 m
Let us consider L asthe slant height of the Cone, then we know that
L2 = r2 +h22
L2 =152 + 7.52
L2 =225 + 56.25
L2 =281.25
L = 12.5 m
Now,
Volume of the cylinder= πR2h1 = V1
V1 =π(10)2 2.5
V1 =250 πm3
Volume of the Cone= 1/3 × 22/7 × r2 × h22 = V2
V2 = 1/3× 22/7 × 102 × 7.5
V2 =250π m3
So, the total capacityof the tent = volume of the cylinder + volume of the cone = V1 +V2
V = 250 π + 250 π
V = 500π m3
Hence, the totalcapacity of the tent is 500π m3
And, the total area ofcanvas required for the tent is S = 2 πRh1 + πrL
S = 2(π)(10)(2.5) +π(10)(12.5)
S = 550 m2
Therefore, the totalcost for canvas is (100) (550) = Rs. 55000