Question -
Answer -
Given,
Base diameter of thecylindrical base of the petrol tank = 21 cm
So, its radius (r)= diameter/2 = 21/2 = 10.5 cm
Height of theCylindrical portion of the tank (h1) = 18 cm
Height of the Conicalportion of the tank (h2) = 9 cm
Now, we know that
The volume of theCylindrical portion (V1) = πr2 h1
V1 =π(10.5)2 18
V1 =6237 cm3
The volume of theConical portion (V2) = 1/3 × 22/7 × r2 × h2
V2 = 1/3× 22/7 × 10.52 × 9
V2 =1039.5 cm3
Therefore, the totalvolume of the tank (V) = 2 x volume of a conical portion + volume of theCylindrical portion
V = V1 +V2 = 2 x 1039.5 + 6237
V = 8316 cm3
So, the capacity ofthe tank = V = 8316 cm3