Question -
Answer -
Given,
Radius of thespherical ball = 3 cm
We know that,
The volume of thesphere = 4/3 πr3
So, it’s volume (V) =4/3 πr3
That the ball ismelted and recast into 3 spherical balls.
Volume (V1)of first ball = 4/3 π 1.53
Volume (V2)of second ball = 4/3 π23
Let the radius of thethird ball = r cm
Volume of third ball(V3) = 4/3 πr3
Volume of thespherical ball is equal to the volume of the 3 small spherical balls.
Now,
Cancelling out thecommon part from both sides of the equation we get,
(3)3 =(2)3 + (1.5)3 + r3
r3 = 33–23– 1.53 cm3
r3 =15.6 cm3
r = (15.6)1/3 cm
r = 2.5 cm
As diameter = 2 xradius = 2 x 2.5 cm
= 5.0 cm.
Thus, the diameter ofthe third ball is 5 cm